Correct option is (d) None of these
Let A = set of aliens having two noses
B = set of aliens having three legs
C = set of aliens having four ears
n(A) = 40, n(B) = 30, n(C) = 20, n(A ∩ B) = 10, n(B ∩ C) = 12, n(C ∩ A) = 5, n(A ∩ B ∩ C) = 3
n(A ∪ B ∪ C) = n(A) + n(B) + n(C) − (n(A ∩ B) + n(B ∩ C) + n(C ∩ A)) + n(A ∩ B ∩ C)
n(A ∪ B ∪ C) = 40 + 30 + 20 − (10 + 12 + 5) + 3
n(A ∪ B ∪ C) = 40 + 30 + 20 − (10 + 12 + 5) + 3
n(A ∪ B ∪ C) = 66
Aliens having any of the deformities = 66
So, aliens without any deformities = 125 − 66 = 59