Correct option is (d) ZN Δ ZP = Z – {0}
Zn → Set of non-negative integers.
Zp → Set of non positive integers.
Z → Set of integers.
E → Set of even integers.
P → Set of prime numbers.
E ∩ P = {2}
Zn ∩ Zp = {0}
Z − Zn = Zp and {0}
Zn Δ Zp = (Zn ∪ Zp) − (Zn ∩ Zp)
= Z − {0}