Correct option is (b) \(\frac x{\sqrt{x^2 + y^2}}\)
\(\tan x = \frac xy\)
\(\tan x =\frac PB= \frac xy\)
Here, P is the perpendicular and B is the base.
We know, square of hypotenuse H2 = P2 + B2
H2 = x2 + y2
H = \(\sqrt{x^2 + y^2}\)
Hence, sin x = \(\frac PH = \frac x{\sqrt{x^2 + y^2}}\)