Question

For the reaction \( 2 A \rightarrow B+3 C ; \) if \( -\frac{d[A]}{d t}=k_{1}[A]^{2} ; \frac{d[B]}{d t}=k_{2}[A]^{2} \); \( \frac{ d [ C ]}{ dt }= k _{3}[ A ]^{2} \) the correct reaction between \( k _{1}, k _{2} \) and \( k _{3} \) is 

(A) \( k _{1}= k _{2}= k _{3} \) 

(B) \( 2 k _{1}= k _{2}=3 k _{2} \) 

(C) \( 4 k _{1}= k _{2}=3 k _{2} \) 

(D) \( \frac{ k _{1}}{2}= k _{2}=\frac{ k _{3}}{3} \)

Answer 1

Correct option is (D) \(\frac{k_1}3 = k_2 = \frac{k_3}3\)

2A → B + 3B

from law of chemical equilibrium