Solve the following. 64 number

Question

Solve the following:

\(\cos^{-1} \frac{x^2 -1}{x^2 + 1} + \tan^{-1} \frac{2x}{x^2 - 1} = \frac{2\pi}3\)

Solve the following : \[ \cos ^{-1} \frac{x^{2}-1}{x^{2}+1}+\tan ^{-1} \frac{2 x}{x^{2}-1}=\frac{2 \pi}{3} \]

Answer 1

Given​

\(\cos^{-1} \frac{x^2 -1}{x^2 + 1} + \tan^{-1} \frac{2x}{x^2 - 1} = \frac{2\pi}3\)