topic capacitance

Question

find equivalent capacitance 

Answer 1

C = C₁ + C₃  

C = 1 + 1

C₅ = 2µF

C = C₂ + C₄

C = 1 + 2

C₆ = 3µF

Then,

\(\frac{1}{C}=\frac{1}{C_5}+\frac{1}{C_6}\)

\(\frac{1}{C}=\frac{1}{2}+\frac{1}{3}\)

\(\frac{1}{C}=\frac{3+2}{6}\)

\(\frac{1}{C}=\frac{5}{6}\)

\(C=\frac{6}{5}\mu F\)