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SO3​(g) is heated in a closed vessel. An equilibrium 2SO3​(g) ⇌ 2SO2​(g) + O2​(g)
is established. The vapour density of the mixture, in which SO3​ is 50% dissociated, is:

(a) 32

(b) 35

(c) 42

(d) 55

1 Answer

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Best answer

Correct option is (a) 32

SO3​(g) is heated in a closed vessel. An equilibrium 2SO3​(g) ⇌ 2SO2​(g) + O2​(g) is established. 

Sulfur trioxide has molar mass of 80 g/mol. It's vapour density (before dissociation) is 

D = \(\frac{80}2\)​ = 40

2 molecules of SO3​ on dissociation gives 3 molecules of gaseous products.

1 molecule of SO3 on dissociation gives \(\frac 32\)​ = 1.5 molecules of gaseous products.

n = 1.5

The vapour density of the mixture, in which SO3​ is 50% dissociated, is 32.

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