Correct option is (a) 32
SO3(g) is heated in a closed vessel. An equilibrium 2SO3(g) ⇌ 2SO2(g) + O2(g) is established.
Sulfur trioxide has molar mass of 80 g/mol. It's vapour density (before dissociation) is
D = \(\frac{80}2\) = 40
2 molecules of SO3 on dissociation gives 3 molecules of gaseous products.
1 molecule of SO3 on dissociation gives \(\frac 32\) = 1.5 molecules of gaseous products.
n = 1.5
The vapour density of the mixture, in which SO3 is 50% dissociated, is 32.