Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
113 views
in Atomic structure by (15 points)
5) wave no \( (\bar{v}) \) of a wave is \( 8200 cm ^{-1} \). Find wavelength and Frequenls.

Please log in or register to answer this question.

1 Answer

0 votes
by (15 points)

Given-

wave number= 8200/cm = 82/m

To find-

1. Wavelength=

λ=1/wave no. 

λ= 1/82 m

λ=0.0121 m 

λ= 1.21×10^(-2) m

2. Frequency=

ν = c/λ

ν = (3*10^(8)m/s) / (1.21*10^(-2)m)

ν = 2.47×10^(10)/s

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...