Question

0.1 mole of a compound of S and Cl on oxidation with conc. HNO₃ and subsequent treatment gave 0.1 mole of PbCl₂ and 0.2 mole of BaSO₄ as precipitates. Determine the molecular formula of the compound.

Answer 1

According to problem

\(S_xCl_y \longrightarrow x SO_4^{2-} + yCl^- \longrightarrow xBaSO_4 + \frac y2PbCl_2\)

0.1 mole of S_xCly = 0.1 x mole of BaSO₄ + \(\frac{0.1 y}2\) mole of PbCl₂

or 0.1 x = 0.2; x = 2

\(\frac{0.1 y}2\) = 0.1; y = 2

\(\therefore \) Molecular formula = S₂Cl₂