Question

An article manufactured by a company consists of two parts A and B. In the process of manufacture of part A. 9 out of 104 parts may be defective. Similarly, 5 out of 100 are likely to be defective in the manufacture of part B. Calculate the probability that the article manufactured will not be defective.

Answer 1

Article will not be defective if both the parts are non defective.

P(A to be defective) = \(\frac{9}{104}\)

P(A not defective) = \(1-\frac{9}{104}=\frac{95}{104}\)

P(B to be defective) = \(\frac{5}{100}=\frac{1}{20}\)

P(B not defective) = \(1-\frac{1}{20}=\frac{19}{20}\)

Since the events are independent

Now, P (None is defective)

\(=\frac{95}{104}\times\frac{19}{20}=\frac{316}{416}=0.87\)