Cost function (C) = \(\frac{x^2}{100}+30x+1600\)
Average cost (A.C) = \(\frac{C}{x}=\frac{x}{100}+30+\frac{1600}{x}\)
Now,
\(\frac{d}{dx}(A.C)=\frac{1}{100}+0-\frac{1600}{x^2}\)
For maximum and minimum cost d/dx (A.C) = 0
\(\therefore \,\frac{1}{100}-\frac{1600}{x^2}=0\)
\(⇒\frac{1600}{x^2}=\frac{1}{100}\)
⇒ x2 = 160000
⇒ x = 400
\(\frac{d^2(A.C.)}{dx^2}=\frac{3200}{x^3}=+ve,\) at x = 400
∴ A.C. is minimum at x = 400.
∴ 400 items must be produced to have a minimum average cost.