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+1 vote
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The total number of electrons present in 18 ml of water (density of water is 1 g ml-1) is

(a) 6.02 x 1023

(b) 6.02 x 1022

(c) 6.02 x 1024

(d) 6.02 x 1025

1 Answer

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Best answer

Correct option is (c) 6.02 x 1024

The total number of electrons present in 18 ml of water is 6.023 × 1024.

Number of electron in one molecule of H2​O is 2 + 8 = 10.

Density = 1 g/ml

∴ 18 ml means 18 g

Moles = \(\frac {18}{18}\) = 1

Molecules = 6.023 × 1023

Electrons = 6.023 × 1023 × 10 = 6.023 × 1024

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