Question

Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at wt. of Fe = 56) present in one molecule of haemoglobin are

(a) 1

(b) 2

(c) 4

(d) 6

Answer 1

Correct option is (c) 4

Percentage of Fe = 0.33 % molecular weight of haemoglobin

Weight of Fe present = \(\frac{0.33}{100} \times 67200\) = 221.76 g

One Fe weighs 55.8 g

Therefore, \(\frac{221.76}{56}\)​ = 4