Question

Number of atoms in 4.25 g of NH₃ is nearly

(a) 1 x 10²³

(b) 1.5 x 10²³

(c) 2 x 10²³

(d) 6 x 10²³

Answer 1

Correct option is (d) 6 x 10²³

No. of moles in 4.25 g of NH₃ = \(\frac{4.25}{17}\) = 0.25

Hence, No. of atoms = 0.25 x 4 × 6.02 × 10²³

= 6.02 x 10²³