Question

The largest number of molecules is in 

(a) 36 g of water 

(b) 28 g of CO₂

(c) 46 g of CH₃OH

(d) 58 g of N₂O₅

Answer 1

Correct option is (a) 36 g of water

36 g of water = \(\frac{36}{18}\) = 2 moles

28 g of CO₂ = \(\frac{28}{44}= \frac {7}{11}\) = 0.64 moles

46 g of CH₃OH = \(\frac{46}{32}\) = 1.44 moles

58 g of N₂O₅ = \(\frac{58}{108}\) = 0.54 moles