If 1 1/2 moles of oxygen combine with Al to form Al2O3, the weight of Al used in the reaction is

Question

If \(1\frac 12\) moles of oxygen combine with Al to form Al₂O₃, the weight of Al used in the reaction is (Al = 27)

(a) 27g

(b) 54 g

(c) 40.5 g

(d) 81 g

Answer 1

Correct option is (b) 54 g

1.5 moles of oxygen (3 g atom) combines with 2 g atom of aluminium.

Hence weight of Al used = 2 x 27 = 54 g