Writing the relevant chemical equation,
\(\underset{32g}S + \underset{22.4 \text{litres}}{O_2} \longrightarrow SO_2\)
Thus 32 g of sulphur require = 22.4 litres of O2
900 g of suphur require = \(\frac{22.4}{32}\) × 900 litres = 630 litres of pure O2
But percentage of oxygen in air by volume = 21% 2
In other words, 21 litres of O2 are present in 100 litres of air
630 litres of O2 100 are present in air = \(\frac{100}{21}\) × 630 litres = 3000 litres
Volume of air required = 3000 litres
