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The equivalent weight of calcium phosphate Ca3(PO4)2 is (Mol. wt. = 310) 

(a) 310/2

(b) 310/6

(c) 310/3

(d) 310

1 Answer

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Correct option is (b) 310/6

2Ca3​(PO4​)2​ → 6Ca+2 + 4(PO4​)3−

Ca3​(PO4​)2

O.S & Ca → +2

MM of Ca3​(PO4​)2​ → 310 gm

Equation mass = \(\frac{\text{Mw of salt}}{\text{charge}}\)

Phosphic = \(\frac{2 \times 310}{6 \times 2}\)

\(\frac{ 310}{6}\)

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