Question

The weight of sulphuric acid required to completely dissolve 10 g of CaCO₃ (at wt. Ca = 40, S = 32) is

(a) 98 g

(b) 49 g

(c) 9.8 g

(d) 0.98 g

Answer 1

Correct option is (c) 9.8 g

CaCO₃ + H₂SO₄ → CaSO₄ + CO₂ + H₂O

Weight of H₂SO₄ required = \(\frac{98 \times 10}{100}\) = 9.8g