Question

0.528 g of a monocarboxylic acid require 6 meq of a base for neutralisation. Sodium salt of this acid on heating with soda-lime will give

(a) ethane

(b) propane

(c) butane

(d) pentane

Answer 1

Correct option is (b) propane

Eq. mass of the acid = \(\frac{0.528\times 1000}{6}\) = 88

Being monobasic, the mol. mass = 88

The acid may be C₃H₇COOH.

C₃H₇COOH \(\xrightarrow {Soda \, lime}\) C₃H₈ (propane)