The oxidation number of \( S \) in \( H _{2} S _{2} O _{8} \) is(a) +2(b) +4(c) +6\( (d)+7 \)

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DeepikaJha · Answer 1 · 2023-07-25T04:00:43+0000

The structure of H₂S₂O8 is given below.

In the structure of H₂S₂O₈, two oxygen atoms are involved in peroxide linkage, hence oxidation number will be −1 (each). Remaining oxygen atoms will have −2 charge. Thus, we can calculate the oxidation state of sulphur (x) as follows:

The oxidation number of \( S \) in \( H _{2} S _{2} O _{8} \) is(a) +2(b) +4(c) +6\( (d)+7 \)

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