Question

Liquid benzene burns in oxygen according to following equation.

2 C₆H₆ (l) + 15 O₂ (g) → 12 CO₂ (g) + 6H₂O (g)

How many litres of oxygen are required for complete combustion of 39 gram of liquid benzene?

(a) 11.2

(b) 22.4

(c) 42

(d) 84

Answer 1

Correct option is (d) 84

Moles of O₂ required to burn 39 g benzene = \(\frac{15 \times 39}{2 \times 78} = \frac{15}4\)

Volume of CO₂ required = \(\frac{15}4\)x 22.4 = 84 L (STP)