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in Continuity and Differentiability by (40.4k points)
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सिद्ध कीजिए कि फलन 
\(f(x) = \begin{cases}x^2-1;&x≥1\\1-x;&x < 2\end{cases}\)  बिन्दु x = 1 पर अवकलनीय नहीं है।

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x = 1 पर बायाँ अवकलज (L.H.D.)

x = 1 पर दायाँ अवकलज (R.H.D.)

अतः फलन x = 1 पर अवकलनीय है।

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