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in Laws of motion by (20 points)
edited by

A uniform rope of mass 2kg which can tolerate maximum tension 80 N at any point find maximum value of F which can be applied on 2 kg block

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1 Answer

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by (41.0k points)

Tmax = 80 N

T = (m2 + m3)a

T = (2 + 3)a

80 = 5a

a = 16 ms-2

F = ma

F = (m1 + m2 + m3) x 16

= (2 + 2 + 3) x 16

= 7 x 16

= 112 N

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