Question

Oxidation states of sulphur in the anions SO₃^2-, S₂O₄^2-, S₂O₆^2- follow the order

(a) SO₃^2- < S₂O₄^2- < S₂O₆^2-

(b) S₂O₄^2- < SO₃^2- < S₂O₆^2-

(c) S₂O₄^2- < S₂O₆^2- < SO₃^2-

(d) S₂O₆^2- < S₂O₄^2- < SO₃^2-

Answer 1

Correct option is (b) S₂O₄^2- < SO₃^2- < S₂O₆^2-

ON of S is SO₃^2- =+4

ON of S is S₂O₆^2- =+5

ON of S is S₂O₄^2- = zero

Remember that S₂O₄^2- has a S-S linkage and ON of the two S of S-S bond is taken as zero.