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(2m×m-3m+10) ÷ (m-5)

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(2m×m-3m+10) ÷ (m-5)

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Given \(\frac{2m^2-3m+10}{m-5}\)

Now (2m2 −3m+10) can be written after dividing by (m−5) as (2m2 −3m+10)=((2m+7)×(m−5))+45 so 45 is remainder and (2m+7) is dividend.

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