Question

[19] The energy of one mole of photons of radiation of frequency \( 2 \times 10^{12} Hz \) in \( J^{2} mol ^{-1} \) is (Nearest integer) (Given: \( h=6.626 \times 10^{-34} / S \) \( \left.N_{A}=6.022 \times 10^{23} mol ^{-1}\right) \) (A) 796 (B) 798 (C) 797 (D) 785

Answer 1

Answer: (B) 798

\(E=Nh\nu\)

\(=6.022\times10^{23}\times6.626\times10^{-34}\times2\times10^{12}\)

\(=798\,J/mole\)