Electric field

Question

ABCD is square of 4cm side.charges of 16×10-9C,-16×10-9c,32×10-9c are located at the points A,C,D respectively.find The intensity of electric field at point B?​​​​​​​

Answer 1

\(E_{byc}=\frac{9\times10(-16\times10^{-9})}{(4\times10^{-2})^2}\)

\(E_{byc}=-9\times10^ 4\)

\(E_{byA}=9\times 10^ 4\)

At D \(\frac{32\times10^{-9}\times9\times10^ 9}{(4\sqrt{2}\times10^ {-2})^ 2}\) 

E_D = 9 x 10⁴

^{⇒ \(-9000\hat{J}+9000\hat{i}+\frac{9000\hat{i}}{\sqrt{2}}-\frac{9000}{\sqrt{2}}\hat{J}\)}

^{⇒ \(\left(9000(1+\frac{1}{\sqrt{2}})\hat{i}+9000(1-\frac{1}{\sqrt{2}})\hat{J}\right)\)}