Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
74 views
in Physics by (840 points)
closed by

A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is 

(a) 100 km

(b) 25 km

(c) 15 km

(d) 10 km

Chapter: Motion and Time

Class: 7

image

What will be the answer for this with it's full explanation.

1 Answer

+1 vote
by (55.0k points)
selected by
 
Best answer

Correct option is (b) 25 km

Given,

Let the speed be 'S' and time be 't' respectively.

S1 = 40 km/hr, S2 = 60 km/hr, t1 = t2 = 15 min ⇒ 15/60 = 0.25 hr.

Since the journey has variable speed, therefore we have to calculate the distance separately for each case.

The total distance covered is D.

D = D1 + D2

D = S1t1 + S2t2 = (S1 + S2)t  [∵ t1 = t2 = t]

D = (40 + 60) x 0.25

D = 100 x 0.25 ⇒ 25 km.

∴ the total distance covered is 25 km.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...