Let
x = number of units of F1 to consume
y = number of units of F2 to consume
Objective Function:
Minimize the cost of consumption, which can be expressed as:
Cost = 6x + 3y (since the cost per unit of F1 is Rs. 6 and F2 is Rs. 3
Constraints:
B1 consumption constraint:
The daily prescribed consumption of B1 should be at least 50 units.
Considering the composition of B1 in F1 and F2, we have:
3x + 5y ≥ 50
B2 consumption constraint:
The daily prescribed consumption of B2 should be at least 60 units. Considering the composition of B2 in F1 and F2, we have:
4x + 3y ≥ 60
Non-negativity constraint:
The number of units of F1 and F2 consumed cannot be negative, so we have:
x ≥ 0
y ≥ 0
The formulated LPP can be summarized as follows:
Minimize: Cost = 6x + 3y
Subject to:
3x + 5y ≥ 50
4x + 3y ≥ 60
x ≥ 0
y ≥ 0
By solving this LPP, we can determine the optimal values of x and y, which represent the number of units of F1 and F2 to consume in order to meet the minimum daily prescribed consumption of B1 and B2 while minimizing the cost of consumption.