A source of potential difference \( V \) is contece to the combination of two identical capaciton, shown in the figure, When key ' \( K \) ' is closed, total energy stored across the combination is Now key ' \( K \) ' is opened and dielectric dielectric constant 5 is introduced between of plates of the capacitors. The total energy slone across the combination is now \( E_{2} \). The ras \( E _{1} / E _{2} \) will be :

Question

A source of potential difference \( V \) is contece to the combination of two identical capaciton, shown in the figure, When key ' \( K \) ' is closed, total energy stored across the combination is Now key ' \( K \) ' is opened and dielectric dielectric constant 5 is introduced between of plates of the capacitors. The total energy slone across the combination is now \( E_{2} \). The ras \( E _{1} / E _{2} \) will be :

Answer 1

(1) Switch is closed

 C_eq = 2C

Energy,

\(E_1 =\frac 12 C_{eq}V^2\)

\(= \frac 12 2C\times V^2\)

\(E_1 = CV^2\)

(2) When switch is opened charge on right capacitor remain CV while potential on left capacitor remain same

Dielectric K = 5

C′ = KC

C′ = 5C