Correct option is (A) not real
\(2x^{2}-4 x+3=0\)
Comparing Equation with \(a x^{2}+b x+c=0\)
a = 2, b = -4, c = 3
We know that,
\(D =b^{2}-4 a c\)
\( =(-4)^{2}-4 \times 2 \times 3\)
= 16 - 24
= -8
Since D<0
\(\therefore \) So, the given Equation has no real roots.