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\(\begin{bmatrix}4&-6\end{bmatrix}\begin{bmatrix}0\\-1\end{bmatrix}=\)

(A) \(\begin{bmatrix}4&-6\\-4&6\end{bmatrix}\)

(B) \(\begin{bmatrix}0&-6\\0&6\end{bmatrix}\)

(C) \(\begin{bmatrix}0&6\end{bmatrix}\)

(D) \(\begin{bmatrix}6\end{bmatrix}\)

1 Answer

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Best answer

Correct option is (D) \(\begin{bmatrix}6\end{bmatrix}\) 

 \(\begin{bmatrix}4&-6\end{bmatrix}\begin{bmatrix}0\\-1\end{bmatrix}= \begin{bmatrix}0+6\end{bmatrix}\)

\(=\begin{bmatrix}6\end{bmatrix}\)

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