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\(-2\begin{bmatrix}3& -5\\5&9\end{bmatrix} =\)

(A) \(\begin{bmatrix}-6& -5\\5&9\end{bmatrix}\)

(B) \(\begin{bmatrix}-6& 10\\5&9\end{bmatrix}\)

(C) \(\begin{bmatrix}-6& 10\\-10&9\end{bmatrix}\)

(D) \(\begin{bmatrix}-6& 10\\-10&-18\end{bmatrix}\)

1 Answer

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Best answer

Correct option is (D) \(\begin{bmatrix}-6& 10\\-10&-18\end{bmatrix}\)

\(-2\begin{bmatrix}3& -5\\5&9\end{bmatrix} = \begin{bmatrix}-6& 10\\-10&-18\end{bmatrix}\)

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