Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
130 views
in Probability by (36.2k points)
closed by

यदि P(A ∪ B) = \(\frac 7{31}\), P(A ∩ B) = \(\frac {24}{31}\) तथा P(A) = \(\frac{12}{31}\) हो तो P(B) =

(A) \(\frac {15}{31}\)

(B) \(\frac {17}{31}\)

(C) \(\frac {19}{31}\)

(D) \(\frac {29}{31}\)

1 Answer

+1 vote
by (35.0k points)
selected by
 
Best answer

Correct option is (C) \(\frac {19}{31}\)

\(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)

\(\frac 7{31} = \frac {12 }{31} + P(B) - \frac {24}{31}\)

\(P(B) = \frac 7{31} + \frac {24}{31} - \frac {12}{31}\)

\(= \frac{7 + 24 - 12}{31}\)

\(=\frac {19}{31}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...