Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
85 views
in Probability by (36.2k points)
closed by

दो स्वतंत्र घटनाओं E और F के लिए P(E ∩ F) =

(A) P(E) + P(F)

(B) P(E).P(F)

(C) P(E) - P(F)

(D) \(\frac{P(E)}{P(F)}\)

1 Answer

+1 vote
by (35.0k points)
selected by
 
Best answer

सही विकल्प है (B) P(E).P(F)

P(E ∩ F) = P(E).P(F)

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...