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S and T are points on sides PR and QR respectively of ∆PQR such that ∠P = ∠RTS prove that ∆RPQ~∆RTS.

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Triangle PQR

Given: ∆PQR the points S and T on sides PR and QR such that ∠P = ∠RTS

To Prove: ∆RPQ~∆RTS

Proof: In ∆RPQ and ∆RTS

∠P = ∠RTS  [Given]

∠PRQ = ∠TRS [Common]

So, ∆RPQ~∆RTS [By AA similarity criterion]

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