Question

Simplify the given algebraic expressions

\(\frac{x^3}{x-y} - \frac{x^3}{x-y}\)

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Answer 1

= \(\frac{x^3}{x-y} - \frac{x^3}{x-y}\)

= \(\frac{x^3 - y^3}{x-y}\) .....(using a³ – b³ = (a – b) (a² + ab + b²))

= \(\frac{(x-y)(x^2 + xy + y^2)}{x-y}\)

= x² + xy + y²