Question

A body, starting from rest, attains a velocity of 20 ms⁻¹ .The time taken by the body in the displacement of 50 m is

Answer 1

u = 0 m/s

v = 20 m/ss = 50 mv² = u² + 2as(20)² = (0)² + 2.a.50a = 4 m/s²v = u + at20 = 0 + 4tt = 5 s

Answer 2

 s = ut + \(\frac {1}{2}\) at²

50 = \(\frac {1}{2}4\)(t)²

t = 5sec

v² − u² = 2as

20² = 2(a) (50)

20 x 20 = 100a

a = 4 m/s²