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in JEE by (70 points)
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A neutral conducting solid sphere of radius R has two spherical cavities of radii a and b as shown in the figure. Centre to centre distance between two cavities is c. qs and qb charge are placed at the centers of cavities respectively. 
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Correct option is (A) \( \frac 1{4\pi \varepsilon_0} \frac{q_a.q_b}{c^2}\)

\(F = \frac{Kq_a.q_b}{c^2}\)

\(\bar F = \frac 1{4\pi \varepsilon_0} \frac{q_a.q_b}{c^2}\)

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