Correct option is a) 3 x 105 W
Given that,
mass of each wagons, m = 25 tonnes
Number of wagons = 60
Speed of train, V = 72 km/hr
= 72 x \(\frac {5}{18}\,m/s\)
= 20 m/s
Frictional force Per tonne, f = 10 N
Total Mass of train = 60 x 25 tonnes
= 1500 tonnes
Total frictional force on train,
F = 1500 x 10 N
= 15000
Power = F.V
Power developed = FV
= 15000 N. x 20 m/s
= 300000 N. m/s
= 3 x 105 W