Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
157 views
in Mathematics by (5.7k points)

Simplify: [5 a5 b2 × 3(a b3)2]/ (15 a2 b).

Please log in or register to answer this question.

1 Answer

0 votes
by (5.7k points)

[5 a5 b2 × 3(a b3)2]/ (15 a2 b)

Using the formula (am)n = amn, we have;

= [(5 × 3) × (a5 b2) × a2 b6]/ (15 a2 b)

= (15 a5+2 b2+6)/ (15 a2 b)

= (a7 b8)/(a2 b)

= a7-2 b8-1

= a5 b7

Therefore, [5 a5 b2 × 3(a b3)2]/ (15 a2 b) = a5 b7.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...