Let the required sum be Rs. x.
S.I = \(\frac{P \times R \times T}{100}\)
= \(\frac{x \times 8 \times 2}{100}\)
= \(\frac{16x}{100}\)
A = P + S.I.
= \(x + \frac{16x}{100}\)
= \(\frac{100x + 16x}{100}\)
= \(\frac{116x}{100}\)
But the amount is Rs. 12122.
\(\frac{116x}{100}\) = 12122
x = \(\frac{12122 \times 100}{116} = 10450\)
Now, S.I = \(\frac{P \times R \times T}{100}\)
= \(\frac{10450 \times 9 \times 32}{100 \times 12}\)
= Rs. 2508
A = P + S.I.
= Rs. 10450 + Rs. 2508
= Rs. 12958