Question

Find the circumcenter of the triangle formed by the lines 3x-y-5=0, x+2y-4=0, 5x+3y+1=0

Answer 1

Given line are
3x – y – 5 = 0 ... (1)
x + 2y – 4 = 0 ... (2)
5x + 3y + 1 = 0 ... (3)
The point of intersection of (1) & (2) is A(2, 1)
The point of intersection of (2) & (3) is B(–2, 3)
The point of intersection of (3) &(1) is C(1, –2)
 Let S
(α,β) be circumcentre of the triangle ABC

We know that SA = SB = SC