The value of the integral

Question

\( \int \frac{\sin \theta \cdot \sin 2 \theta\left[\sin ^{6} \theta+\sin ^{4} \theta+\sin ^{2} \theta\right] \sqrt{2 \sin ^{4} \theta+3 \sin ^{2} \theta+6} d \theta}{1-\cos 2 \theta} \)

Answer 1

Let sinθ=t,cosθ dθ = dt