The de Broglie wavelength is the wavelength, λ, associated with a massive particle and is related to its momentum, p, through the Planck constant, h
\(\lambda = \frac {h}{p}\)
For an electron accelerated by potential V,
\(qV = \frac {p^2}{2m}\)
⇒ \(p = \sqrt {2mqV}\)
Hence \(\lambda = \frac {h}{\sqrt {2mqV}}\)