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A 2m long wire is stretched by 0.5cm. Calculate the elastic potential energy per unit volume if the Young's modulus of the material of the wire is Y=8×1010 N/m-2

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The potential energy stored in a stretched wire is given by,

From Hooke's law,

\(U = 2.5\times10^4\,Jm^{-3}U \) will be the potential energy stored in a stretched wire.

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