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What is the nature of roots of the quadratic equation \(6x^2 - 3x + 5 = 0\)?

(A) Real and unequal

(B) Real and equal

(C) Not real

(D) None of these

1 Answer

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Best answer

Correct option is (C) Not real

The given quadratic equation is

\(6 x^{2}-3 x+5=0\)

Here,

\(a=6, b =-3 \text { and } c=5\)

\(D =b^{2}-4 a c\)

\(=(-3)^{2}-4 \times 6 \times 5\)

\(=9-120\)

\(=-111\)

\(\therefore \Delta <0\)

Hence the equation has no real roots.

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