Correct option is (C) Not real
The given quadratic equation is
\(6 x^{2}-3 x+5=0\)
Here,
\(a=6, b =-3 \text { and } c=5\)
\(D =b^{2}-4 a c\)
\(=(-3)^{2}-4 \times 6 \times 5\)
\(=9-120\)
\(=-111\)
\(\therefore \Delta <0\)
Hence the equation has no real roots.