Correct option is (B) \(220 \text{ cm}^3\)
Given that the external and internal radius of pipe is \(4 \mathrm{~cm}\) and \(3 \mathrm{~cm}\) and length is \(10 \mathrm{~cm}\).
Let \(r_{1}\) and \(r_{2}\) be the external and internal radius and \(h\) be length of pipe.
\(\therefore\) Volume of metal pipe = External Volume of pipe - Internal volume of pipe
\(=\pi r_{1}^{2} h-\pi r_{2}^{2} h\)
\(=\pi h\left(r_{1}^{2}-r_{2}^{2}\right)\)
\(=\frac{22}{7} \times 10 \mathrm{~cm}\left(\left(4 \mathrm{~cm}\right)^{2}-\left(3 \mathrm{~cm}\right)^{2}\right)\)
\(=\frac{22}{7} \times 10 \mathrm{~cm}\left(16 \mathrm{~cm}^{2}-9 \mathrm{~cm}^{2}\right) \)
\(=\frac{22}{7} \times 10 \mathrm{~cm} \times 7 \mathrm{~cm}^{2}\)
\(=220 \mathrm{~cm}^{3}\)
