Question

For what value of p, terms (2p + 1), 13, (5p - 3) are in A.P. ?

(A) 3

(B) 4

(C) 12

(D) 6

Answer 1

Correct option is (B) 4

If is given that \(2 p+1,13,5 p-3\) are three consecutive terms of an A.P. We know that for a sequence \(a, b, c\) in A.P. We can write, \(b-a=c-b\).

For the given sequence in A.P, we can write,

\(13-(2 p+1) =(5 p-3)-13\)

\(13-2 p-1 =5 p-3-13\)

\(13-1+3+13 =5 p+2 p\)

\(28 =7 p\)

\(\therefore p =\frac{2 8}{7}=4\)

Therefore, the value of p is 4.

Answer 2

AnkushLather, hello

For an arithmetic progression, 13-(2p+1) would equal (5p-3)-13 and p would equal 4.

The correct answer is (B) 4